{"id":16544,"date":"2024-12-14T06:26:17","date_gmt":"2024-12-14T06:26:17","guid":{"rendered":"https:\/\/freshgovtjobs.in\/nit-rourkela-jrf-recruitment-apply\/"},"modified":"2024-12-14T06:26:17","modified_gmt":"2024-12-14T06:26:17","slug":"nit-rourkela-jrf-recruitment-apply-20241209","status":"publish","type":"post","link":"https:\/\/freshgovtjobs.in\/nit-rourkela-jrf-recruitment-apply-20241209\/","title":{"rendered":"NIT Rourkela JRF\u00a0Recruitment 2024 – Apply For 1 Vacancies in Sundergarh"},"content":{"rendered":"

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NIT Rourkela JRF Recruitment 2024<\/strong> NIT Rourkela Recruitment 2024 notification for JRF\u00a0 posts was released. The total number of vacancies under this recruitment for JRF\u00a0 1 <\/strong>Posts. Candidates who are eligible and interested to apply for NIT Rourkela\u00a0 JRF\u00a0 Recruitment 2024 can get more information on the official website,<\/p>\n

The written examination for Odisha <\/strong>JRF\u00a0 recruitment 2024. Candidates who checked the eligibility criteria and applied for the recruitment will be able to download the NIT Rourkela JRF Recruitment Notification 2024 here. Check more details such as salary, selection process, result etc. of the recruitment process at this page.<\/p>\n

NIT Rourkela has released JRF\u00a0 1 <\/strong>vacancies which will be available for Sundergarh ,Odisha<\/strong>\u00a0State. The candidates who will apply for the job will download admit card for JRF Exam.<\/p>\n

NIT Rourkela JRF Recruitment 2024 Apply Soon<\/strong><\/p>\n\n\n\n\n\n\n\n\n\n
\u00a0Name of the Organization<\/td>\nNIT Rourkela<\/td>\n<\/tr>\n
\u00a0No. of Posts<\/td>\n1 <\/strong>Vacancies<\/td>\n<\/tr>\n
\u00a0Name of the Posts<\/td>\nJRF<\/td>\n<\/tr>\n
Job Category<\/td>\nGovernment jobs<\/td>\n<\/tr>\n
Job Location<\/td>\nSundergarh , Odisha<\/strong><\/td>\n<\/tr>\n
Age<\/strong><\/td>\n18 TO 45 Years<\/td>\n<\/tr>\n
Official Website<\/td>\nhttps:\/\/www.nitrkl.ac.in\/ <\/strong><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

Education Qualification:<\/strong><\/p>\n

PG<\/p>\n

Age Limit: <\/strong><\/p>\n